Work and KE
introduction:
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we did not take the picture of the set up, this one is from the other classmate |
Theorem:
Object gain speed or lose speed base on the work on it, due to Fnet do on it.
we do work: integral of x with changing F= (1/2)mv^2
Date:
Before we release the cart, we tie another side of the spring on the force senor. We collect both date.
mass=600g= 0.6kg
The force senor find the date is the read line figure. We integral it by position as the
red area = 1.154 m*N
Then we find the changing kinetic energy by speed which came to 2.173m/s from 0.780m/s
(1/2) m*v1^2 - (1/2)m*v2^2 = 0.5*0.6*2.173*2.173-0.5*0.6*0.78*0.78=1.234m*N
Conclusion:
We get 1.154 m*N from force and 1.234m*N from speed
have a error about 6% said that our result is close enough